3x^2-4x+5=2x^2-4x+41

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Solution for 3x^2-4x+5=2x^2-4x+41 equation:


Simplifying
3x2 + -4x + 5 = 2x2 + -4x + 41

Reorder the terms:
5 + -4x + 3x2 = 2x2 + -4x + 41

Reorder the terms:
5 + -4x + 3x2 = 41 + -4x + 2x2

Add '4x' to each side of the equation.
5 + -4x + 4x + 3x2 = 41 + -4x + 4x + 2x2

Combine like terms: -4x + 4x = 0
5 + 0 + 3x2 = 41 + -4x + 4x + 2x2
5 + 3x2 = 41 + -4x + 4x + 2x2

Combine like terms: -4x + 4x = 0
5 + 3x2 = 41 + 0 + 2x2
5 + 3x2 = 41 + 2x2

Solving
5 + 3x2 = 41 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
5 + 3x2 + -2x2 = 41 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
5 + 1x2 = 41 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
5 + 1x2 = 41 + 0
5 + 1x2 = 41

Add '-5' to each side of the equation.
5 + -5 + 1x2 = 41 + -5

Combine like terms: 5 + -5 = 0
0 + 1x2 = 41 + -5
1x2 = 41 + -5

Combine like terms: 41 + -5 = 36
1x2 = 36

Divide each side by '1'.
x2 = 36

Simplifying
x2 = 36

Take the square root of each side:
x = {-6, 6}

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